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12*10^2x=29.53
We move all terms to the left:
12*10^2x-(29.53)=0
We add all the numbers together, and all the variables
12*10^2x-29.53=0
Wy multiply elements
120x^2-29.53=0
a = 120; b = 0; c = -29.53;
Δ = b2-4ac
Δ = 02-4·120·(-29.53)
Δ = 14174.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{14174.4}}{2*120}=\frac{0-\sqrt{14174.4}}{240} =-\frac{\sqrt{}}{240} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{14174.4}}{2*120}=\frac{0+\sqrt{14174.4}}{240} =\frac{\sqrt{}}{240} $
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